小通道内制冷剂两相流动摩擦压降关联式分析

Processing math: 100%

刘勖诚, 谷波, 曾炜杰, 杜仲星, 田镇

Analysis of Frictional Pressure Drop Correlations of Refrigerant Two-Phase Flow in Mini-Channel

LIU Xucheng, GU Bo, ZENG Weijie, DU Zhongxing, TIAN Zhen

表1 均相模型关联式

Tab.1 Correlations of homogeneous equilibrium model

文献编号	关联式	文献编号	关联式
[9]	$\frac{1}{μ_{tp}}$ = $\frac{x}{μ_{g}}$ + $\frac{1 - x}{μ_{l}}$	[12]₄	μ_tp= $\frac{1}{2}$ [μ_l $\frac{2 μ_{l} + μ_{g} - 2 (μ_{l} - μ_{g}) x}{2 μ_{l} + μ_{g} + (μ_{l} - μ_{g}) x}$ + μ_g $\frac{2 μ_{g} + μ_{l} - 2 (μ_{g} - μ_{l}) (1 - x)}{2 μ_{g} + μ_{l} + (μ_{g} - μ_{l}) (1 - x)}$ ]
[10]	μ_tp= $\frac{2 μ_{g} + μ_{l} - 2 (μ_{g} - μ_{l}) (1 - x)}{2 μ_{g} + μ_{l} + (μ_{g} - μ_{l}) (1 - x)}$	[13]	μ_tp=xμ_g+ $(1 - x)$ μ_l
[11]	μ_tp=μ_l ${[(1 - x) + x {(ρ_{l} / ρ_{g})}^{0.5}]}^{- 1}$	[14]	μ_tp= $\frac{x ρ_{l} μ_{g} + (1 - x) ρ_{g} μ_{l}}{x ρ_{l} + (1 - x) ρ_{g}}$
[12]₁	μ_tp=μ_l $\frac{2 μ_{l} + μ_{g} - 2 (μ_{l} - μ_{g}) x}{2 μ_{l} + μ_{g} + (μ_{l} - μ_{g}) x}$	[15]	ω= $\frac{x ρ_{l}}{ρ_{g} + x (ρ_{l} - ρ_{g})}$ μ_tp=ωμ_g+ $(1 - ω) (1 + 2.5 ω)$ μ_l
[12]₂	μ_tp=μ_g $\frac{2 μ_{g} + μ_{l} - 2 (μ_{g} - μ_{l}) (1 - x)}{2 μ_{g} + μ_{l} + (μ_{g} - μ_{l}) (1 - x)}$	[16]	μ_tp= $\frac{μ_{l} μ_{g}}{μ_{g} + x^{1.4} (μ_{l} - μ_{g})}$
[12]₃	μ_tp= $\frac{1}{4}$ { $(3 x - 1)$ μ_g+ $(2 - 3 x)$ μ_l+ $\sqrt[]{{[(3 x - 1) μ_{g} + (2 - 3 x) μ_{l}]}^{2} + 8 μ_{g} μ_{l}}$ }	[17]	μ_tp=C_μμ_l $(1 - x)$ +μ_gx, C_μ=6.195-9.178p_r